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 Post subject: Need help fo my math Exam
PostPosted: Thu May 16, 2013 5:30 am 
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i have to find out how many blocks are in the layers http://prntscr.com/1558e9
like that to find that out i have to use this http://prntscr.com/1558gp

but if i do that with 2 layers i get this
(2x2^3+3x2^2+2)
---------------
6
I get 5 >.> it suppose to be 4! only if i use layer i get the correct answer ? what am i doing wrong?

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 5:47 am 
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nmv anjou/rosa/unkown explained the formula count all the layes togheter not 1
to find out he blocks for 1 layer only u need to multy them like layer 5 has 25 blocks u need ot to do 5x5

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:02 am 
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how the hell can u get 5 from that :|

(2x2^3+3x2^2+2)
---------------
6

= (2 * 8 + 3 * 4 + 2) / 6 = 78 / 6 = 13

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:11 am 
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aister wrote:
how the hell can u get 5 from that :|

(2x2^3+3x2^2+2)
---------------
6

= (2 * 8 + 3 * 4 + 2) / 6 = 78 / 6 = 13



its solved now

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Last edited by Excl1 on Thu May 16, 2013 6:35 am, edited 1 time in total.

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:18 am 
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if 2*2*2 isn't equal 8, my whole life is a big lie

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:22 am 
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and i though Pythoragus and Heron were complicated.

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:25 am 
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to find the total blocks u have to add the number of blocks per layer

it's a square, so u will have n^2 blocks (with n is the layer index)

the total would be:

n^2 + (n - 1)^2 + (n - 2)^2 + ... + 2^2 + 1^2

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 6:26 am 
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shti forgot to delete that pert out ur right aister xD BUT I DID WROTE WAHT MY CACULATOR SAYED MABY ITS BROKEN

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 8:12 am 
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hold on this thing gets super easy if the top layer has only 1 block and you know how many layer they are

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 Post subject: Re: Need help fo my math Exam
PostPosted: Thu May 16, 2013 5:15 pm 
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aister wrote:
how the hell can u get 5 from that :|

(2x2^3+3x2^2+2)
---------------
6

= (2 * 8 + 3 * 4 + 2) / 6 = 78 / 6 = 13


How did you get 78?!?

= (2 * 8 + 3 * 4 + 2) / 6
= (  16 +  12 + 2) / 6
= (       30 ) / 6
= 5
Durp!


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